producto de dos binomios con un termino en comun

(x-1)(x+3b)=
(ab+12)(ab+2c)=
(x + 9) (x + 4) =
(x –ab)(x – 2)
(x + 6) (x – 1) =
(x – 4) (x + 2) =
(x + m) (x + y) =
(x + 11) (x – 7) =
(x – 6) (x – 9) =
(x +13)(x – 7) =
(x – 10) (x +z)=
(x – c) (x + d) =
(1/4yz-a)(2/5x-a)=
(5y-z)(5y-x)=
(3/4xy+12)(1/4xy+3)=